which of the following are correct? 1) both a and b, 2) only a, 3) only b, 4) neither a nor b a) Solve S. S = 1-1+1-1+1..... S = 1 -(1-1+1-1+1.....) S = 1 - S S = 1/2 b) Given pi^2 / 8 = 1/1^2 + 1/3^2 + 1/5^2 + 1/7^2+... Solve S. S = 1/1^2 + 1/2^2+ 1/3^2 + 1/4^2 + 1/5^2 + 1/6^2 + 1/7^2+... S = (1/1^2 + 1/3^2 + 1/5^2 + 1/7^2+...) + (1/2^2+ 1/4^2 + 1/6^2 + 1/8^2+...) S = pi^2 / 8 + 1/4 * S S = pi^2 / 6
microsat 发表于 2025-06-27 13:31 which of the following are correct? 1) both a and b, 2) only a, 3) only b, 4) neither a nor b a) Solve S. S = 1-1+1-1+1..... S = 1 -(1-1+1-1+1.....) S = 1 - S S = 1/2 b) Given pi^2 / 8 = 1/1^2 + 1/3^2 + 1/5^2 + 1/7^2+... Solve S. S = 1/1^2 + 1/2^2+ 1/3^2 + 1/4^2 + 1/5^2 + 1/6^2 + 1/7^2+... S = (1/1^2 + 1/3^2 + 1/5^2 + 1/7^2+...) + (1/2^2+ 1/4^2 + 1/6^2 + 1/8^2+...) S = pi^2 / 8 + 1/4 * S S = pi^2 / 6
Many rules for finite sums may fail for infinite sums. Using them blindly could lead to mistakes such as (a) which is itself a divergent series (meaning it has no sum). It is also well-known that a conditionally convergent series can be rearranged so that it would converge to any value you want (or become divergent), e.g. 1/1-1/2+1/3-1/4+1/5 -.... The series in (b), on the other hand, is absolutely convergent and behaves much more predictably.
a) Solve S.
S = 1-1+1-1+1..... S = 1 -(1-1+1-1+1.....) S = 1 - S S = 1/2
b) Given pi^2 / 8 = 1/1^2 + 1/3^2 + 1/5^2 + 1/7^2+... Solve S.
S = 1/1^2 + 1/2^2+ 1/3^2 + 1/4^2 + 1/5^2 + 1/6^2 + 1/7^2+... S = (1/1^2 + 1/3^2 + 1/5^2 + 1/7^2+...) + (1/2^2+ 1/4^2 + 1/6^2 + 1/8^2+...)
S = pi^2 / 8 + 1/4 * S S = pi^2 / 6
a) is incorrect, b) is correct
谢谢!
同样是代入法,为何a是错误的呢?
能详细说说吗?
标题看用户名系列
绝对收敛了解一下
收敛和不收敛的区别
只能收敛的才能用代入法?
那一般怎么快速的证明一个级数和是收敛的呢?
微積分2
LZ 还审过稿呢
Many rules for finite sums may fail for infinite sums. Using them blindly could lead to mistakes such as (a) which is itself a divergent series (meaning it has no sum). It is also well-known that a conditionally convergent series can be rearranged so that it would converge to any value you want (or become divergent), e.g. 1/1-1/2+1/3-1/4+1/5 -.... The series in (b), on the other hand, is absolutely convergent and behaves much more predictably.